[nooodl]

Monochrome image file to .chr file:

INFILE = 'infile.bmp'
OUTFILE = 'outfile' # .chr

from PIL import Image

im = Image.open(INFILE)
ch = open(OUTFILE + '.chr', 'wb')
assert im.size == (256, 112)
l = list(im.getdata())

for i in range(256):
    cx, cy = (i % 32) * 8, (i / 32) * 14
    for j in range(14):
        pos = (cy + j) * 256 + cx
        byte = l[pos:pos+8]
        byte = sum(int(x > 0) << 7 - i for (i, x) in enumerate(byte))
        ch.write(chr(byte))
ch.close()

Image to 80x50 .pal and .mzm:

INFILE = 'infile'
OUTFILE = 'outfile' # .mzm and .pal

import struct
from PIL import Image

def palettecolors(im):
    l = im.resize((16, 1))
    l.putdata(range(16))
    return l.convert('RGB').getdata()

im = Image.open(INFILE).convert('P', palette=Image.ADAPTIVE, colors=16)
width, height = im.size

# .pal
pal = []
for c in palettecolors(im):
    for i in c:
        pal.append(chr(i/4))
pal = ''.join(pal)
open(OUTFILE + '.pal', 'wb').write(pal)

# .mzm
mzm = open(OUTFILE + '.mzm', 'wb')
mzm.write('MZM2')
mzm.write(struct.pack('<2H', width, height / 2))
mzm.write('\0\0\0\0\0\1\0\0')

data = list(im.getdata())
for i in range(0, height, 2):
    top    = data[(i + 0) * width:(i + 1) * width]
    bottom = data[(i + 1) * width:(i + 2) * width]
    for bg, fg in zip(top, bottom):
        mzm.write(struct.pack('2B', 0xDC, fg + (bg << 4)))
mzm.close()

The latter is pretty specific, but hey. Also, you'll need PIL: http://www.pythonwar...m/products/pil/

This post has been edited by nooodl: 11 October 2011 - 08:50 PM

[GetDizzy]

Totally using the top one in CharCon Redux. Why reinvent the wheel?